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No best answer has yet been selected by chrisguk. Once a best answer has been selected, it will be shown here.
For more on marking an answer as the "Best Answer", please visit our FAQ.As the question is stated, there isn't a unique answer. You could have 29 piles each worth 44p, for example - either 4 x 10p + 4 x 1p or 2 x 20p + 2 x 2p.
Can you give an indication as to what would make one solution better than another? Fewer coins? Fewer piles? Piles that differ from each other but still give the same number of each denomination across the total sum (if that is possible)?