Cashier performance calculation help please

[cdwrover123]

Manager compares performance of 3 cashiers (a,b,c) in particular time period 12.00 - 14.00. How long it took 1 customer to be served? 1 cashier served 50 during that period. X bar = service time for each cashier per 1 customer. S = standard deviation by each cashier per 1 customer. What would be a)the use of the statistics? B)mean of these statistics? Show workings

[bednobs]

your statistics are incomplete aren't they? Is it supposed to be accompanied by a graph perhaps? how can you do a comparison when you've only given 1 result?
Therefore answer to a) = none at all

[CovKid]

%0 in 2 hours is 2.4 mins per cust. (assuming no gaps between customers). Compare that to a standard for x-bar? Straight comparison not much use, need to allow for natural variation. Could develop a confidence interval for true mean. Seems to rely on a lot of assumptions about the underlying distribution of service times (often negative exponential is assumed). What course are you studying? It sounds like a business/management course taught by someone "none too competent".

[CovKid]

Sorry. I hit %0 when I meant 50.

[mike11111]

Where are these cashiers? In a bank, supermarket? Makes a diffference, methinks.

[CovKid]

Could also compare cashiers. I think you might need to pool the samples to find SD. Are the individual significantly different. I'm a bit rusty...some years since I taught the stuff on Bus.Mangt courses!!

[twix123]

I think that the Standard Deviation was when all 3 cashiers went of to lunch together!

I wonder what the next futile question from rover will be?

[kinell]

50 customers in two hours....

definitely not abbey/santander

might be a proper bank though