Crosswords0 min ago
Lottery spread betting
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No best answer has yet been selected by shyted. Once a best answer has been selected, it will be shown here.
For more on marking an answer as the "Best Answer", please visit our FAQ.On the first lottery occasion - before the selection even starts, that is - there are 49 balls in the machine, any one of which might be that night's bonus-ball. The odds against any given one - let's say you've guessed No 15 - of these coming up are, therefore, 48 to 1 against...ie only one is 'right' (No 15) and the other 48 are 'wrong'.
The same 48 to 1 against odds apply to the second lottery occasion, when you chose perhaps No 37. The odds against getting both 15 and 37 in that sequence over the two occasions are calculated by multiplying the odds for each occasion...ie 48 X 48, which = 2304 to 1 against. As I said, I don't know how to relate that to 'spread' betting, but I hope you can.
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