Donate SIGN UP

Lottery spread betting

Avatar Image
shyted | 14:42 Mon 15th Dec 2003 | How it Works
1 Answers
What would you make Saturdays bonus ball multiplied by Wednesdays bonus ball ? There are two schools of thought .. 49 squared , divided by 2 = 1200.5 or 49 divide 2 , squared = 600.25 ?? I believe someone else told me that 70% of the possible outcomes would fall under 470 or something like that. Can anyone out there in mathland shed some light on this ?
Gravatar

Answers

Only 1 answerrss feed

Best Answer

No best answer has yet been selected by shyted. Once a best answer has been selected, it will be shown here.

For more on marking an answer as the "Best Answer", please visit our FAQ.
If you know how to translate standard odds into spread-betting format - I can't! - here are the standard figures. Basically, you seem to be asking: "What are the odds re guessing beforehand the bonus-ball number correctly over two separate lotteries?"

On the first lottery occasion - before the selection even starts, that is - there are 49 balls in the machine, any one of which might be that night's bonus-ball. The odds against any given one - let's say you've guessed No 15 - of these coming up are, therefore, 48 to 1 against...ie only one is 'right' (No 15) and the other 48 are 'wrong'.

The same 48 to 1 against odds apply to the second lottery occasion, when you chose perhaps No 37. The odds against getting both 15 and 37 in that sequence over the two occasions are calculated by multiplying the odds for each occasion...ie 48 X 48, which = 2304 to 1 against. As I said, I don't know how to relate that to 'spread' betting, but I hope you can.

Only 1 answerrss feed

Do you know the answer?

Lottery spread betting

Answer Question >>

Related Questions

Sorry, we can't find any related questions. Try using the search bar at the top of the page to search for some keywords, or choose a topic and submit your own question.