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Wildlife
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How does a leopard ( or another predator ) know where the 100 square miles of his territory starts and ends ?
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No best answer has yet been selected by Bazile. Once a best answer has been selected, it will be shown here.
For more on marking an answer as the "Best Answer", please visit our FAQ.It can well be narrowed down to what he states Bazile. You have to remember there's been a lot of preservation / conservation going for some number of years now, and with the GPS collar that they fix to a lot of wildlife they can track their movements for many months.
After so long of tracking the collar can be set to release at a given time without any further stress to the animal.
After so long of tracking the collar can be set to release at a given time without any further stress to the animal.
https:/ /en.wik ipedia. org/wik i/Terri tory_(a nimal)
more than you ever need or want to know on this.
I have always wondered if the male had to do a round to freshen the marks - Kinda distance and time thing, and it is pretty obvious the distance is gonna be a circle. NOT the most efficient for packing males, a square / rectangle would be.
My dog found a chicken carcass under someone'w wall. and checked every day for 21 d to see if another had miraculously grown there. But this is food seeking rather than marking.
For those who have done and passed 11+ maff ; I suggest an obvious eqn (without tiresome derivation) for a time distance smell relation is :
.
∂2u/∂t2 = c2 ∂2u∂x2 and its solutions. ( 1 dimensional wave equation and er easily extended to two )
I should get out more
more than you ever need or want to know on this.
I have always wondered if the male had to do a round to freshen the marks - Kinda distance and time thing, and it is pretty obvious the distance is gonna be a circle. NOT the most efficient for packing males, a square / rectangle would be.
My dog found a chicken carcass under someone'w wall. and checked every day for 21 d to see if another had miraculously grown there. But this is food seeking rather than marking.
For those who have done and passed 11+ maff ; I suggest an obvious eqn (without tiresome derivation) for a time distance smell relation is :
.
∂2u/∂t2 = c2 ∂2u∂x2 and its solutions. ( 1 dimensional wave equation and er easily extended to two )
I should get out more