Body & Soul3 mins ago
Prospect Magazine, July Enigma
14 Answers
3 people, A, B and C, have integer ages. A total of 5 digits is required to construct the 3 ages and no digit is repeated.
28 years ago, B was twice the age that A was 4 years ago.
In 11 years time, A will be 3 times the age that C will be in 9 years time.
What are the ages of A, B and C ?
This one is confusing me, as it seems that if the present ages of A, B and C are X, Y and Z, then (Y-28) = 2(X-4), ie (Y-28) = (2X-8), so Y = (2X + 20) and therefore Y = X + 10. This would clearly mean that at least one digit of the ages is repeated, which is not allowed.
Please can someone advise, what am I overlooking ?
28 years ago, B was twice the age that A was 4 years ago.
In 11 years time, A will be 3 times the age that C will be in 9 years time.
What are the ages of A, B and C ?
This one is confusing me, as it seems that if the present ages of A, B and C are X, Y and Z, then (Y-28) = 2(X-4), ie (Y-28) = (2X-8), so Y = (2X + 20) and therefore Y = X + 10. This would clearly mean that at least one digit of the ages is repeated, which is not allowed.
Please can someone advise, what am I overlooking ?
Answers
25,70 and 3? 28, 76 and 4? 31,82, 5?
11:17 Tue 05th Aug 2014
Whoops ! In my defence O-Level Maths was 1977, still I shouldn't have made that daft error !
I also forgot to mention that A's age is a prime number, so there is a unique solution.
Thanks very much for all your help folks !
PS I think this is still a 'live' puzzle - the closing date is usually in the first half of the month, but does anyone know for sure ? That would explain why this month's puzzle isn't available yet online.
I also forgot to mention that A's age is a prime number, so there is a unique solution.
Thanks very much for all your help folks !
PS I think this is still a 'live' puzzle - the closing date is usually in the first half of the month, but does anyone know for sure ? That would explain why this month's puzzle isn't available yet online.
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