Please can anyone give me a HINT on how to solve this question - which may or maynot have something to do with the names being in CAPITAL letters??
ANNE has one child, JOANNA has three children, JOYCE has four children, JUNE and MILLICENT each have five children. LOGICALLY, how many children do AMANDA and LULU have between them?
Please note - I do not want anyone to tell me the answer, I am just looking for a HINT.
Total disaster!! Had at least three answers and went for the very obvious, which I should have know would be TOO obvious - knew there would be a catch, and tried to work it out myself but got an answer something liike 10.23 miles, but did not think it would be down to decimal places - how wrong could I be!
Bad Luck, but I got easy peasy wrong. I put GM Brands instead of Diego?
A quizzing friend had directed me to a 'chestnuts' site which had less soldiers marching so I multiplied that answer by 4 and hoped for the best.
Thanks to you I've finished the logic. I was barking up the right tree because I remembered the Bournemouth one from ages ago but hadn't started it yet.
Everyone will have got it now!
I'm sure it said Diego on the answer sheet.
Last month he marked one of mine wrong - dehorn- and I sent 4 dictionary definitions by return but he ignored me. Poll - ugh - as in referees.
Am thinking of taking up knitting!
ANNE ( First vowel A plus the second vowel E) 1+2 = 3 minus number of vowels (2) = One child
JOANNA (Fourth vowel O + A + A) 4 + 1 + 1 = 6 minus three vowels = Three children
Hence AMANDA 3 - 3 = none
LULU = Eight (Fifth vowel U 5 + 5 = 10 minus two vowels = eight) so between them they have eight children.
I still haven't a clue but now we've been given an extra fortnight, I might work it out or guess! I don't know how I got into Mensa. The Exam was nothing like this!
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