ChatterBank2 mins ago
Ditloids they keep coming
10 Answers
6 = n of pnp
23 = n of l in the ra
4 = g w
3 = g of c (p, p & f)
9 = s r of e
23 = n of l in the ra
4 = g w
3 = g of c (p, p & f)
9 = s r of e
Answers
Best Answer
No best answer has yet been selected by Jan Merolant. Once a best answer has been selected, it will be shown here.
For more on marking an answer as the "Best Answer", please visit our FAQ.
-- answer removed --
-- answer removed --
-- answer removed --
-- answer removed --
The appendix on p1807 of Chambers Dictionary (2003 Edition) gives a Russian alphabet of 33 letters. Shepherd's glossaryof graphic signs and symbols (1971) gives names (and symbols) for 37 letters, not all of which have Roman equivalents. True-type web versions seem to have less, 26 I think, but they're so close I'm not sure whether some are one or two
I can't relocate your "Hard Ditloids" list so I'll post this here:
23 Equals Two Times Thirteen Take Three
(Given by SKCOLL on Tue 28/09/04)
Incidentally, if our gremlins start posting part replies every time you hit your space bar, try doing your message in Word and pasting the whole message into the box. Then it all gets through in one, though sometimes peppered with HTML commands.
23 Equals Two Times Thirteen Take Three
(Given by SKCOLL on Tue 28/09/04)
Incidentally, if our gremlins start posting part replies every time you hit your space bar, try doing your message in Word and pasting the whole message into the box. Then it all gets through in one, though sometimes peppered with HTML commands.
You can find an updated list on my site http://www.creativepuzzels.nl/spel/speel1/frameng.htm
Go to language/Language Equations/Ditloids if you are interested in solving these hard ones. Thank for you help. Jan
Go to language/Language Equations/Ditloids if you are interested in solving these hard ones. Thank for you help. Jan
Related Questions
Sorry, we can't find any related questions. Try using the search bar at the top of the page to search for some keywords, or choose a topic and submit your own question.