Religion & Spirituality0 min ago
Maths Problem
27 Answers
I can't find a special section for Maths questions in Topics, so will post it here in the hope that someone can help. It is for a child whose teacher would not explain it to him (or give the answer!)
2x over x-1 minus 7x -3 over x squared - 1
The answer and bit of guidance with how to tackle the problem would be much appreciated.
2x over x-1 minus 7x -3 over x squared - 1
The answer and bit of guidance with how to tackle the problem would be much appreciated.
Answers
Best Answer
No best answer has yet been selected by grasscarp. Once a best answer has been selected, it will be shown here.
For more on marking an answer as the "Best Answer", please visit our FAQ.A huge thank you to input from piggynose, quinie, mickrog, bibblebub, willyjmartin, old geezer, jsnhghs, dr b and ellipsis. The child is around 13 years old Squarebear. I will get him to ask the teacher what is the answer when I see him tomorrow, and if/when the teacher does what teachers are supposed to do, I will let you all know what he says.
I agree willyjmartin. More haste, less correctness on my part, I'm afraid.
There are a couple of bracket errors in your solution however.
To talk grasscarp through it ...
2x/(x-1) - (7x-3)/(x^2 - 1)
Factorise the (x^2-1) ... gives (x+1)(x-1)
2x/(x-1) - (7x-3)/((x+1)(x-1))
Provide a common denominator by mutiply the top and bottom of the first expression by (x+1)
2x(x+1)/((x+1)(x-1)) - (7x-3)/((x+1)(x-1))
Multiply out the numerator (top) of the first expression and put the whole lot over the common denominator:
(2x^2 +2x -7x +3)/((x+1)(x-1))
Simplify:
(2x^2 -5x +3)/((x+1)(x-1))
Factorise 2x^2 - 5x +3 ... gives (2x -3)(x-1)
((2x -3)(x-1))/((x+1)(x-1))
Cancel (x-1) from top and bottom:
(2x -3)/(x+1)
There are a couple of bracket errors in your solution however.
To talk grasscarp through it ...
2x/(x-1) - (7x-3)/(x^2 - 1)
Factorise the (x^2-1) ... gives (x+1)(x-1)
2x/(x-1) - (7x-3)/((x+1)(x-1))
Provide a common denominator by mutiply the top and bottom of the first expression by (x+1)
2x(x+1)/((x+1)(x-1)) - (7x-3)/((x+1)(x-1))
Multiply out the numerator (top) of the first expression and put the whole lot over the common denominator:
(2x^2 +2x -7x +3)/((x+1)(x-1))
Simplify:
(2x^2 -5x +3)/((x+1)(x-1))
Factorise 2x^2 - 5x +3 ... gives (2x -3)(x-1)
((2x -3)(x-1))/((x+1)(x-1))
Cancel (x-1) from top and bottom:
(2x -3)/(x+1)