Quizzes & Puzzles1 min ago
Relativity
10 Answers
On the ground a spaceship measures 25 m in length. Later in the day Isaac goes to space. After the spaceship reaches cruise speed, Albert find that its length has contracted to 10 m. What is the speed of the spaceship?
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Not sure why people are just taking the ratio of the two lengths -- the relationship is given by a Lorentz factor 1/Sqrt[1-(v^2)/(c^2)], so that a contraction of 25m to 10 m gives a speed of:
Contracted Length = Original Length / Lorentz factor
10=25/(1/Sqrt[1-(v^2)/(c^2)])
10/25= Sqrt[1-(v^2)/(c^2)]
(10/25)^2=[1-(v^2)/(c^2)]
(10/25)^2= 1-(v^2)/(c^2)
(v^2)/(c^2)=1-(10/25)^2
v/c=Sqrt[1-(10/25)^2]
v=c*Sqrt[1-(10/25)^2]
v=c*Sqrt[1-0.4^2]
v=c*Sqrt[1-0.16]
v=c*Sqrt[0.84]
v=c*0.9165...
v=299792458*0.9165...
v=274,764,326 m/s (or about 275 million metres per second, or just 0.92*c).
Contracted Length = Original Length / Lorentz factor
10=25/(1/Sqrt[1-(v^2)/(c^2)])
10/25= Sqrt[1-(v^2)/(c^2)]
(10/25)^2=[1-(v^2)/(c^2)]
(10/25)^2= 1-(v^2)/(c^2)
(v^2)/(c^2)=1-(10/25)^2
v/c=Sqrt[1-(10/25)^2]
v=c*Sqrt[1-(10/25)^2]
v=c*Sqrt[1-0.4^2]
v=c*Sqrt[1-0.16]
v=c*Sqrt[0.84]
v=c*0.9165...
v=299792458*0.9165...
v=274,764,326 m/s (or about 275 million metres per second, or just 0.92*c).