Mass Of Co2 Formed In Hcl+Na2Co3 Reaction?

[carlcarlcarl]

2HCl + Na2CO3 => 2NaCl + CO2 +H2O

HCl and Na2CO3 both have volume of 20cm3, concentration 2M.
The question is what mass of CO2 in g is produced.

I calculated that the number of moles for the limiting Na2CO3 is 0.0016, then m=n x Mr makes the mass of CO2 0.0704 g. However, the real answer I was given by the exam board is 0.88. I don't know what I haven't tried and I ran out of ideas. Can anyone tell me what my mistake is?

[fiction-factory]

Can you briefly set out how you arrived at your answer please, carl. I can't remember all the atomic weights ( in know C and O but not sodium). i'll get some pen and paper out later to check your calculation.

[fiction-factory]

I have done it and get two answers (can't decide which is right until I check it again)- one is the 0.88 given by the setter and the other is double that , i.e. 1.76.
I suspect the 0.88 is right.
I don't get yours at all. I don't see where your 0.0016 comes from (I get 0.04 or 0.02 moles). Even if I were to use your figure of 0.0016 moles I'd get 0.0768g rather than 0.0704g.

It would help if you could set out your working so I can look more closely.

[fiction-factory]

Oops sorry- should have used pen and paper: I would get your 0.0704 if I used your calculated moles figure. But I still don't see where your moles figure came from- I get a much higher figure which results in a much higher weight for CO2

[fiction-factory]

Just did it again with pen and paper and I still get the same answer for the weight of CO₂ . Yours looks wrong to me. Do you want to set out how you got 0.0704?

[fiction-factory]

Did you resolve this, carlcarlcarl? You can reply to your own questions to add information, comments, etc