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Solubility

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ChemStump | 02:04 Tue 27th Mar 2007 | Science
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I'm doing an experiment to determine solubility of NaCl in water at 25 degrees C. I sthere a constant I should get as an answer or can I get any answer. I keep getting 4 grams of salt in 5.5 grams of solution which is 72% is this right?
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The solubility of NaCl at 25�C is 36g per 100ml water

Using the same units as yourself, that is 36g salt + 100g water, or 36g salt in 136 g solution

That is equivalent to 1.46g in 5.5g of solution (nothing like what you found) = 26.5%

Check your practical methods for error.
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Thanks a lot gen 2. My chem teacher said the instruments werent calibrated well so she expected a really awkward answer, but even with this answer I have cud i say the solubility is 4 grams of nacl in 5.5 grams of solution. That wud be the correct way to say it right? Or do I have to say it in terms of grams of solute in grams of solvent (instead of solution)
You would normally quote the solubility as I did in my answer and state it as g per 100ml

Your 5.5 g of solution = 4g of solute + 1.5g solvent (water)

Since 1g of water occupies 1 ml, you have 4g NaCl in 1.5 ml water. Scaling up that gives an astounding 267 g NaCl per 100 ml water.

As I previously stated, the answer should be 36g. You have an experimental error in excess of 700% so it is your experimental technique that needs further investigation.

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