yeah, try f x t = (m1 x v) - (m2 x u)
where f = force, t = collision time, m1 = mass of cue, v = initial velocity of cue, m2 = mass of ball, u = velocity of ball
rearrange to get: [(m1 x v) - (f x t)] / m2 = u
i think that a typical cue weighs about 0.6kg
a ball weighs about 0.1kg
average human could apply a force of say 75N?
with a cue speed of 5m/s
call the collision time 0.1s
then with these made up numbers, you have a ball speed of 72m/s.
no need to worry about friction and stuff, as the maximum speed will be as the ball leaves the cue.