Spam & Scams1 min ago
gravitation
if a hole is made in the earth from top to bottom and a small stone is thrown, what is the status of that stone
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Some people believe that the stone would plummet to the centre then continue for a while before being dragged back to the centre. It would oscillate like this for a while before eventually settling at the centre.
However, it is impossible to make a hole through the Earth and so is a theoretical question that makes no sense.
However, it is impossible to make a hole through the Earth and so is a theoretical question that makes no sense.
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Tetjam, the Earth as we know it is only a thin crust on the outside. Most of the planet is molten rock and other plonk. So, as squarebear says, it is impossible to drill a hole right through as it will immediately fill up. In fact, I would postulate that once through the mantle the inside pressure would blow the drill, the drilling truck and the whole drilling installation to kingdomcome.
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Varsh
I assume (unlike the ABers who have answered thus far) that you wish to know what would happen in principle, i.e. a thought experiment. It is irrelevant whether it is possible to drill a hole through the Earth or not. The question is,
"What would happen if there WERE a hole through the Earth ?"
The answer is, the stone would continue travelling until it nearly reached the surface at the opposite side, then fall back towards the centre, and so on, each time not going quite so far, until eventually ending up stationary (and weightless) at the centre.
This of course assumes a spherically symmetric Earth.
I assume (unlike the ABers who have answered thus far) that you wish to know what would happen in principle, i.e. a thought experiment. It is irrelevant whether it is possible to drill a hole through the Earth or not. The question is,
"What would happen if there WERE a hole through the Earth ?"
The answer is, the stone would continue travelling until it nearly reached the surface at the opposite side, then fall back towards the centre, and so on, each time not going quite so far, until eventually ending up stationary (and weightless) at the centre.
This of course assumes a spherically symmetric Earth.
Get real! You've drilled a hole through the Earth (I wonder what percentage of the Earth's surface is 'opposite' another piece of land, by the way?) and by some miracle lined it up perfectly with the team digging from the other side and you expect me to believe you're going to throw in a little stone? No way. You're going to be chucking in something that wouldn't look out of place at Stonehenge!
Your little stone is going to reach its terminal velocity so quickly and it's going to get a very disappointing distance past the centre of the Earth before it starts its journey back. Plus use of the word 'thrown' rather than 'dropped' leads me to believe it's going to spend an inordinate amount of time bouncing off the walls, slowing it down even more.
Your little stone is going to reach its terminal velocity so quickly and it's going to get a very disappointing distance past the centre of the Earth before it starts its journey back. Plus use of the word 'thrown' rather than 'dropped' leads me to believe it's going to spend an inordinate amount of time bouncing off the walls, slowing it down even more.
nightmare is right: this is purely hypothetical question which has nothing to do with practicalities. To refuse to consider it on the grounds that such a hole is impossible is as unimaginative as Fred Hoyle's objection to the idea of monkeys bashing typewriters - he complained that the machines would soon jam up due to lack of oil and then fall to pieces. Give me strength!
I don't know how to solve this without resorting to calculus, which I'll have to brush up on.
The problem is that the 32ft per second per second which we glibly quote as the acceleration due to gravity has that value only at the surface of the earth. As you fall through the earth, more and more of the earth's mass (which is what matters) moves 'above' you, reducing the gravitational force pulling you 'down'. At the centre of the earth, gravity is zero.
So the stone's acceleration will progressively reduce as it falls. Does this mean that it will stop at the earth's centre? What is for sure is that it won't overshoot by very far, if at all.
I think we'd better work it out again...
I don't know how to solve this without resorting to calculus, which I'll have to brush up on.
The problem is that the 32ft per second per second which we glibly quote as the acceleration due to gravity has that value only at the surface of the earth. As you fall through the earth, more and more of the earth's mass (which is what matters) moves 'above' you, reducing the gravitational force pulling you 'down'. At the centre of the earth, gravity is zero.
So the stone's acceleration will progressively reduce as it falls. Does this mean that it will stop at the earth's centre? What is for sure is that it won't overshoot by very far, if at all.
I think we'd better work it out again...
We could use the hole to disperse some of the excess sea water created by our good friend global warming. That would be a really interesting diving experience. Just a lod of water hanging in the middle of the 'hole'.
When starting in the midlle, I assume that no matter what direction you swam in, it would always be 'up'. A bit like standing on the North pole and only being able to move off Southwards.
When starting in the midlle, I assume that no matter what direction you swam in, it would always be 'up'. A bit like standing on the North pole and only being able to move off Southwards.
