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How do I work out...
Can some one please tell me how I work out how much water 15 meters of 1/2 inch copper tube will hold. Thanks.
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Assume it to be 10mm (D=10mm) � the internal cross sectional area is given by:-
2 x π x r x r = 2 x 3.142 x 0.005 x 0.005 = 0.000157 square metres
Multiply this by the length of the tube (15) to give a volume of 0.002355 cubic metres, or 2.355 litres.
It is early in the morning, so perhaps someone could check my maths.
Assume it to be 10mm (D=10mm) � the internal cross sectional area is given by:-
2 x π x r x r = 2 x 3.142 x 0.005 x 0.005 = 0.000157 square metres
Multiply this by the length of the tube (15) to give a volume of 0.002355 cubic metres, or 2.355 litres.
It is early in the morning, so perhaps someone could check my maths.
-- answer removed --
. . . no big. I too often miscalculate after a long night of extended overtime at the neighborhood nuke plant
. . . I get a volume of 0.95 litre for an id of 9mm?
Most copper tubing designated as "1/2 inch" will have an inside diameter equal to or exceeding 1/2 inch which varies with wall thickness and is not necessarily consistent along its length. Therefore I have assumed a 1/2 inch inside diameter for the following discussion:
Volume pertains to a three dimensional space as within a box, sphere or other containment. For a circle, (the cross section of tubing) the two dimensional area subsumed can be found by multiplying the radius (half the inside diameter) by the radius and multiplying the product (r�) by pi (π = ~ 3.1416). Multiplying this by the third dimension, (length), specifies the volume.
First convert dimensions to common (equivalent) units
1/2 inch diameter = 1.27 cm (centimeters)
15 metres length = 1500 cm
Plug variables into the formula for volume of a cylinder:
π x radius� x length = volume
(remember that radius = diameter / 2)
π x 0.635cm� x 1500cm = 1900cm� = 1.9 litres
Your �1/2 inch� copper tubing might hold more or less water than that. Given the inconsistency of copper tubing interiors I found rov�s methods worthy of serious consideration . . . or you could fill the tube and drain the water into a measuring beaker.
Most copper tubing designated as "1/2 inch" will have an inside diameter equal to or exceeding 1/2 inch which varies with wall thickness and is not necessarily consistent along its length. Therefore I have assumed a 1/2 inch inside diameter for the following discussion:
Volume pertains to a three dimensional space as within a box, sphere or other containment. For a circle, (the cross section of tubing) the two dimensional area subsumed can be found by multiplying the radius (half the inside diameter) by the radius and multiplying the product (r�) by pi (π = ~ 3.1416). Multiplying this by the third dimension, (length), specifies the volume.
First convert dimensions to common (equivalent) units
1/2 inch diameter = 1.27 cm (centimeters)
15 metres length = 1500 cm
Plug variables into the formula for volume of a cylinder:
π x radius� x length = volume
(remember that radius = diameter / 2)
π x 0.635cm� x 1500cm = 1900cm� = 1.9 litres
Your �1/2 inch� copper tubing might hold more or less water than that. Given the inconsistency of copper tubing interiors I found rov�s methods worthy of serious consideration . . . or you could fill the tube and drain the water into a measuring beaker.
Would someone please help me to point out where I've gone wrong. Using above formula I get 3.1416 x 1.27 = 3.99cm (circumference of circle) x 0.635 (radius) = 2.53cm (square cm circle area) x 1500 = 3800 cubic cm = 3.8 litres. Grr... I seem to end up with double of mibsies result.
I couldn't give a hoot about a cylinder's volume before this Q, but now it is driving me crazy.
I couldn't give a hoot about a cylinder's volume before this Q, but now it is driving me crazy.
The volume (three dimensional space) of a rectangle is equal to the area of one face (any face will do) times its extention in the third dimension.
volume = (height x width) x depth
For a cylinder the face corresponds to the two dimensional area of the cross-section (a circle). Multiply this by the extension in the third dimension, height (or length) gives the volume.
The area subsumed by a circle equals pi x radius x radius or π r�
Remember this: The area of a circle equals π r squared
No! π r'nt squared. π r round. Cornbread r squared!
don�t mind me
volume = (height x width) x depth
For a cylinder the face corresponds to the two dimensional area of the cross-section (a circle). Multiply this by the extension in the third dimension, height (or length) gives the volume.
The area subsumed by a circle equals pi x radius x radius or π r�
Remember this: The area of a circle equals π r squared
No! π r'nt squared. π r round. Cornbread r squared!
don�t mind me
Thanks claymore.
I'm just a curious (some say nosey) old ******!
Incidentally, I make it 1.7 litres as well (pi times the radiius (6mm) squared times 15 metres).
So enough for about three decent sized mugs.
The only problem I see is that I cannot imagine the heater will raise the temperature of the water to a sufficient level to brew the tea. Ideally it should be boiling. If it does perchance approach boiling you will have trouble with expansion etc. and may have to install a safety device or an expansion vessel.
You might have to settle for instant coffee or cocoa.
I'm just a curious (some say nosey) old ******!
Incidentally, I make it 1.7 litres as well (pi times the radiius (6mm) squared times 15 metres).
So enough for about three decent sized mugs.
The only problem I see is that I cannot imagine the heater will raise the temperature of the water to a sufficient level to brew the tea. Ideally it should be boiling. If it does perchance approach boiling you will have trouble with expansion etc. and may have to install a safety device or an expansion vessel.
You might have to settle for instant coffee or cocoa.