A solution containing 3.5 mmoles/l of an absorbing compound was diluted 1 in 80 and then read at 670nm in a spectrophotometer using a 1cm sample holder.
If the measured aborbance was 0.37, what was the corresponding transmittance?Calculate the molor absoptivity of the compound at the wavelength used.
factor30 - I don't want to be pedantic but the absence of units indicates that 42 is the transmittance.
If it were the molor absoptivity I'm sure joggerjayne would have said 42 M^-1 cm^-1.
That still leaves the question regarding the absoptivity. Do you want dsl to fail?
Oops, sorry joggerjayne. I thought this was a wind-up, you know, 42 being the answer to the great question of life, the universe and everything. But, darn me, the answer is 42!
thanks guys for the help!! and your concerns bout not wanting me to fail 'eltelioni'!! but 'factor 30' its not that i just want the answer for homework i really want to understand how u guys were able to work it out so i know for future reference. i just cant seem to figure it out how you guys mastered the answer 42???
This could be tricky in plain text, but here goes.
A = absorbance
T = transmittance
I = intensity of light after passing through the sample
J = intensity of the light before passing through the sample
A = -log(I/J) using log to base 10
and T = I/J
so A= -log(T)
so T = 10^(-A) (10 raised to the power -A)
so T = 10^(-0.37)
using Google as a calculator, that gives 0.426579519
which I would round to 0.43
Transmittance is often expressed as a percentage, so multiply by a hundred to give 43.