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BBC Facts
Quote from the BBC website
"The crossover point on a pair of scissors when they are smartly closed is moving faster than the speed of light"
Is that right, if so, how?
"The crossover point on a pair of scissors when they are smartly closed is moving faster than the speed of light"
Is that right, if so, how?
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Without wishing to get too bogged down in the question, Geezer, I just thought I�d raise a point of pedantry under your �two cars� scenario.
The two cars would not be receding at 1.5c (c = speed of light) as nothing can travel relative to another body at more than c.
Newtonian Physics dictates that the relative velocity of two bodies travelling (relative to a fixed point) at velocities u and v is equal to (u+v).
However Einstein�s physics (as explained by his theories on relativity) considers that no body may travel relative to another at at speed greater than c. The formula for calculating their relative speeds becomes:
(u+v) / (1+(uv/c2))
At low velocities there is very little difference between the two calculations. However, as velocities approaching c are considered there is considerable disparity.
Using this formula the speed of recession of the two cars is 0.96c or thereabouts.
The two cars would not be receding at 1.5c (c = speed of light) as nothing can travel relative to another body at more than c.
Newtonian Physics dictates that the relative velocity of two bodies travelling (relative to a fixed point) at velocities u and v is equal to (u+v).
However Einstein�s physics (as explained by his theories on relativity) considers that no body may travel relative to another at at speed greater than c. The formula for calculating their relative speeds becomes:
(u+v) / (1+(uv/c2))
At low velocities there is very little difference between the two calculations. However, as velocities approaching c are considered there is considerable disparity.
Using this formula the speed of recession of the two cars is 0.96c or thereabouts.