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TCP segment headers and converting to octets and binary numbers

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shaunnutley | 00:44 Tue 04th Mar 2008 | Technology
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if a TCP segment's 4-bit header length is represented by the denary number 10 then how many octets would this be?
I calculated this to convert to 1010 as a binary number and then to 12 octets. Could the segments 32-bit sequence number be converted to a binary number in the same way if its denary value was 45000? Would the answer be 1010 1111 1100 1000?
I'd be grateful if anyone can expand on this.
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an octet is an eight digit number(bin)
255 = 11111111 - this is a single octet or byte
so then 10 does = 1010 (1x8+1x2)
half a byte(or 4 bin digits) = a nibble (yes honestly!)

a standard ip v4 address is only 4 octets (8 bytes = 32 bits)

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