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skillszone | 08:53 Tue 11th Jul 2006 | Quizzes & Puzzles
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There are 3 persons X, Y and Z. On some day, X lent cars to Y and Z as many as they had. After a month Y gave as many cars to X and Z as many as they have. After a month Z did the same thing. At the end of this transaction each one of them had 24. Find the cars each originally had?
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X = 42 , Y = 6 and Z = 24
Method: Solve the simultaneous equations
2(X - Y - Z) = 24
4Y = 24
-X - Y +3Z = 24

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