I Need Help Coding

[bob221443]

I have a mostly finished grade calculator that needs help getting finished up and the syntax errors being worked out. It is written in python 3:



studentGradeMath = input("Enter student letter grade for Math - ").upper()
studentGradeWriting = input("Enter student letter grade for Writing - ").upper()
studentGradeReading = input("Enter student letter grade for Reading- ").upper()
studentGradeAttendance = input("Enter student letter grade for Attendance- ").upper()
studentGradeHistory = input("Enter student letter grade for History - ").upper()

if studentGradeMath == "A":
print("4")
elif studentGradeMath == "A-":
print("3.5")
elif studentGradeMath == "B":
print("3")
elif studentGradeMath == "B-":
print("2.5")
elif studentGradeMath == "C":
print("2")
elif studentGradeMath == "C-":
print("1.5")
elif studentGradeMath == "D":
print("1")
elif studentGradeMath == "D-":
print("0.5")
else studentGradeMath == "F":
print("0")

if studentGradeWriting == "A":
print("4")
elif studentGradeWriting == "A-":
print("3.5")
elif studentGradeWriting == "B":
print("3")
elif studentGradeWriting == "B-":
print("2.5")
elif studentGradeWriting == "C":
print("2")
elif studentGradeWriting == "C-":
print("1.5")
elif studentGradeWriting == "D":
print("1")
elif studentGradeWriting == "D-":
print("0.5")
else studentGradeWriting == "F":
print("0")

if studentGradeHistory == "A":
print("4")
elif studentGradeHistory == "A-":
print("3.5")
elif studentGradeHistory== "B":
print("3")
elif studentGradeHistory == "B-":
print("2.5")
elif studentGradeHistory == "C":
print("2")
elif studentGradeHistory == "C-":
print("1.5")
elif studentGradeHistory == "D":
print("1")
elif studentGradeHistory == "D-":
print("0.5")
else studentGradeHistory == "F":
print("0")

if studentGradeAttendance == "A":
print("4")
elif studentGradeAttendance == "A-":
print("3.5")
elif studentGradeAttendance == "B":
print("3")
elif studentGradeAttendance == "B-":
print("2.5")
elif studentGradeAttendance == "C":
print("2")
elif studentGradeAttendance == "C-":
print("1.5")
elif studentGradeAttendance == "D":
print("1")
elif studentGradeAttendance == "D-":
print("0.5")
else studentGradeAttendance == "F":
print("0")

if studentGradeReading == "A":
print("4")
elif studentGradeReading == "A-":
print("3.5")
elif studentGradeReading == "B":
print("3")
elif studentGradeReading == "B-":
print("2.5")
elif studentGradeReading == "C":
print("2")
elif studentGradeReading == "C-":
print("1.5")
elif studentGradeReading == "D":
print("1")
elif studentGradeReading == "D-":
print("0.5")
else studentGradeReading == "F":
print("0")

[Tuvok]

Python was not a language I learnt, but give an example of the sytax error you are getting.

[bob221443]

Tuvok, this syntax error i have been getting has come up when it says else studentGradeMath == "F":
print("0")

i don t see any issue with the line, but something is there

[rockyracoon]

if studentGradeMath == "A":
print("4")
elif studentGradeMath == "A-":
print("3.5")
elif studentGradeMath == "B":
print("3")
elif studentGradeMath == "B-":
print("2.5")
elif studentGradeMath == "C":
print("2")
elif studentGradeMath == "C-":
print("1.5")
elif studentGradeMath == "D":
print("1")
elif studentGradeMath == "D-":
print("0.5")
else:
print("0")

else statements don't have a conditional, and ensure the print statements are indented.

[CrapAtCryptics]

else?

[Tuvok]

Would the else statement have to be altered for the other ifs?

[rockyracoon]

I’ll ask my son as he put the answer in. It’s all Dutch to me.

[Calibax]

Although I am not familiar with Python3 the logic would suggest Rocky is correct.
'Else' means 'if none of the above conditions are met' and requires a command like 'print' rather than another condition. This applies to the last statement for each of the paragraphs (subjects).

[ToraToraTora]

you could cut it down by 90% if you used a look up table.

[JimF]

I also don't know Python but, as has been hinted, this hugely bloated code could be reduced and simplified greatly by using an array-type structure to store the look up keys and values. If I were writing this in C#, I'd be using a Dictionary generic control.

[bob221443]

Yes, it can be shortened, but i have been bored and i recently learn three new coding languages with nothing to do with them.

[vetuste_ennemi]

As other posters have said, Bob, we'd prefer a program which looks something (not that I speak Python) like:

print ("Your grade ", YourGrade, " gives you a score of", Scores[YourGrade])

[bob221443]

I fixed and finished it. thank you everyone. you can customize the calculator and other peices of it and add or remove as you see fit:

studentGradeMath = input("Enter student letter grade for Math - ").upper()
studentGradeWriting = input("Enter student letter grade for Writing - ").upper()
studentGradeReading = input("Enter student letter grade for Reading- ").upper()
studentGradeAttendance = input("Enter student letter grade for Attendance- ").upper()
studentGradeHistory = input("Enter student letter grade for History - ").upper()

if studentGradeMath == "A":
print("4")
elif studentGradeMath == "A-":
print("3.5")
elif studentGradeMath == "B":
print("3")
elif studentGradeMath == "B-":
print("2.5")
elif studentGradeMath == "C":
print("2")
elif studentGradeMath == "C-":
print("1.5")
elif studentGradeMath == "D":
print("1")
elif studentGradeMath == "D-":
print("0.5")
else:
print("0")

if studentGradeWriting == "A":
print("4")
elif studentGradeWriting == "A-":
print("3.5")
elif studentGradeWriting == "B":
print("3")
elif studentGradeWriting == "B-":
print("2.5")
elif studentGradeWriting == "C":
print("2")
elif studentGradeWriting == "C-":
print("1.5")
elif studentGradeWriting == "D":
print("1")
elif studentGradeWriting == "D-":
print("0.5")
else:
print("0")

if studentGradeHistory == "A":
print("4")
elif studentGradeHistory == "A-":
print("3.5")
elif studentGradeHistory== "B":
print("3")
elif studentGradeHistory == "B-":
print("2.5")
elif studentGradeHistory == "C":
print("2")
elif studentGradeHistory == "C-":
print("1.5")
elif studentGradeHistory == "D":
print("1")
elif studentGradeHistory == "D-":
print("0.5")
else:
print("0")

if studentGradeAttendance == "A":
print("4")
elif studentGradeAttendance == "A-":
print("3.5")
elif studentGradeAttendance == "B":
print("3")
elif studentGradeAttendance == "B-":
print("2.5")
elif studentGradeAttendance == "C":
print("2")
elif studentGradeAttendance == "C-":
print("1.5")
elif studentGradeAttendance == "D":
print("1")
elif studentGradeAttendance == "D-":
print("0.5")
else:
print("0")

if studentGradeReading == "A":
print("4")
elif studentGradeReading == "A-":
print("3.5")
elif studentGradeReading == "B":
print("3")
elif studentGradeReading == "B-":
print("2.5")
elif studentGradeReading == "C":
print("2")
elif studentGradeReading == "C-":
print("1.5")
elif studentGradeReading == "D":
print("1")
elif studentGradeReading == "D-":
print("0.5")
else:
print("0")





def add(x, y, g, f, t):
return x + y + g + f + t




print("Select operation.")
print("1.Add")


choice = input("Enter choice(1):")

num1 = int(input("Enter first number: "))
num2 = int(input("Enter next number: "))
num3 = int(input("Enter next number: "))
num4 = int(input("Enter next number: "))
num5 = int(input("Enter next number: "))

if choice == '1':
print(num1,"+",num2, "+",num3,"+",num4, "+",num5,"=", add(num1,num2,num3,num4,num5))

else:
print("Invalid input")