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In A Billiards Game, The White Cue Ball Hits The Black Ball, Moving The Black Ball To The Right While The Cue Ball Moves To The Left. If The Action Force Is Applied By The Cue Ball To The Black Ball, Which Force Is The Reaction Force?

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morgannesti | 18:52 Fri 13th Nov 2020 | Science
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In a billiards game, the white cue ball hits the black ball, moving the black ball to the right while the cue ball moves to the left. If the action force is applied by the cue ball to the black ball, which force is the reaction force?
A. The friction applied by the table to the cue ball.
B. The force applied by the stick to the cue ball
C. The force exerted by the black ball to the cue ball.
D. the force of gravity on the cue ball
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Coursework should be done by the student.
Listing out their questions may cause a ban for spamming.
I didn’t think there was a black ball in billiards.
As has been pointed out, this is a trick question because there's no black ball in billiards, just one red and two white cue balls.

Anyway, given the principal that energy cannot be created or destroyed, the kinetic energy from the swing of the cue (which the OP calls the 'stick') is transferred from the tip of the cue to the cue ball, with part of it lost as the ball travels across the baize, until the cue hits the target ball. At this point, the energy is dissipated according to the left-hand rule and the resultant resting position defined by subtracting nines according to the law of overhead underhang.
No black ball in billiards. There is a white ball with a small black spot.
Billiards is played with three balls : one red, one plain white and one white with a black dot.
American?

Pocket billiards?

Definitely American...just read other Q's

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In A Billiards Game, The White Cue Ball Hits The Black Ball, Moving The Black Ball To The Right While The Cue Ball Moves To The Left. If The Action Force Is Applied By The Cue Ball To The Black Ball, Which Force Is The Reaction Force?

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