ChatterBank1 min ago
Really hard physics ( for me anyway )
16 Answers
Please help with the following:
2 trains going in the same direction @ 30m/s with a 600m gap.
Train in front (T1) has 8 carriages and 200 people and the engine cannot be turned off.
There is 9km of track left, if the second train (T2) can connect with T1 it can remotely turn off engine. But must connect going same speed.
Specifications:
Each carriage = 5.8x10tothepowerof3 kg
Each engine = 1.4x10tothepowerof4 kg
Max. driving force = 6.3kN
Max. braking force = 6.okN
Max. velocity = 180km/hr
Engine max. load = 8 full carriages
carriage capacity = 80 people
Thank you very much.
2 trains going in the same direction @ 30m/s with a 600m gap.
Train in front (T1) has 8 carriages and 200 people and the engine cannot be turned off.
There is 9km of track left, if the second train (T2) can connect with T1 it can remotely turn off engine. But must connect going same speed.
Specifications:
Each carriage = 5.8x10tothepowerof3 kg
Each engine = 1.4x10tothepowerof4 kg
Max. driving force = 6.3kN
Max. braking force = 6.okN
Max. velocity = 180km/hr
Engine max. load = 8 full carriages
carriage capacity = 80 people
Thank you very much.
Answers
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The second train can catch up by going faster than 45m/s but then it won't be doing the same speed so like Brachiopod I'm not sure what you are asking and all the other info is irrelevant but perhaps catching up is not what you are asking.
More info please!
The second train can catch up by going faster than 45m/s but then it won't be doing the same speed so like Brachiopod I'm not sure what you are asking and all the other info is irrelevant but perhaps catching up is not what you are asking.
More info please!
I've got it !!!
The answer is that the impulse imparted per fare-paying passenger is;
2.6 kNm �^-1
(2.6 kiloNewton metres per pound Sterling)
(This assumes that;
the acceleration due to gravity approximates to 10ms^-2;
each passenger is on a Super-Saver Apex Return;
and that;
no-one has flushed the toilet between Kettering and Market Harborough.)
The answer is that the impulse imparted per fare-paying passenger is;
2.6 kNm �^-1
(2.6 kiloNewton metres per pound Sterling)
(This assumes that;
the acceleration due to gravity approximates to 10ms^-2;
each passenger is on a Super-Saver Apex Return;
and that;
no-one has flushed the toilet between Kettering and Market Harborough.)
The question is implied. The latter train needs sufficient accelerative power and braking power to catch up with the first, out-of-control, train before it reaches the end of the track.
We do need more info though, the engineers train - is it just one engine? how much do the passengers weigh?
The question needs to be broken down into two parts, the stopping distance required by T1 (before reaching the end of the track) after its engine has been turned off (and brakes applied, I assume), given its total weight, braking power and velocity.
Subtract this stopping distance from the 9km you have, and this is the amount of distance (and hence time) T2 has to speed up and slow down to catch T1.
Its best to start with a visualisation - a time vs velocity graph, where distance can be calculated by area under the graph.
We do need more info though, the engineers train - is it just one engine? how much do the passengers weigh?
The question needs to be broken down into two parts, the stopping distance required by T1 (before reaching the end of the track) after its engine has been turned off (and brakes applied, I assume), given its total weight, braking power and velocity.
Subtract this stopping distance from the 9km you have, and this is the amount of distance (and hence time) T2 has to speed up and slow down to catch T1.
Its best to start with a visualisation - a time vs velocity graph, where distance can be calculated by area under the graph.
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