Daily Mail Mindbender 2 Dec

[ginger1945]

Im sure ive solved similar in past but cant get a a handle method to solve ie
'Jamilah and Mick Cars race round circular track constant speed start at same point in opposite directions and meet every 30 seconds. Moving in sme direction they meet every 120 seconds.
Track 1800 metres circumference and Jamilah slowest how fast Mick.

Tia

[JJ109]

In 30 seconds the total distance travelled going in opposite directions = 1800m
Combined Speed = 1800 / 30= 60 metres per second

In 120 seconds therefore the combined distance travelled = 120 * 60 = 7200 metres
7200 / 1800 = 4 laps
Therefore Mick is travelling 4 times as fast as Jamilah

60metres per second * 4/5 = 48 metres per second and Jamilah 12 metres per second

Check
30 seconds
Mick 48 * 30 = 1440 metres
Jamilah 12 * 30 = 360 metres
Total = 1800 meters = correct so far

120 seconds
Mike = 120 * 48 = 5760 yards
Jamilah = 120 * 12 = 1440 yards
Total = 7200 yards

[JJ109]

^^ Forget that - wrong logic!

[JJ109]

If they travel 4 laps before they meet again then it means that
Mikes speed is Jamilah's speed + 1/4 of Jamilah's speed
Mike = 1.25 Jamilah's speed

60 metres per second = 2.25 Jamilah
Jamilah = 60/2.25 = 26.67 metres per second
Mike =33.33 metres per second

In 120 seconds Jamilah hasgone 26.67 * 120= 3200 metres
Mike has gone 4000 metres

[ginger1945]

Ta - preferred first- will cogitate- old age thanks

[JJ109]

First is definitely wrong - if he is travelling 4 times as fast he will meet Jamilah before half way on his second lap and 4 laps total need to be travelled by both. Jamilah's speed has to be a lot closer to Mick's for them to go 4 laps combined.