Example:- 5 R in the O F = 5 rings in the Olympic flag I'm stuck on the last 19 of 100 of these:- 9 B S 10 C 6 S on a C 12 L of H 6 B in an O 3 B G G 1111 F N of C 3 A in a T 24 L in a G A 7 D S 168 S in a S of D 21 S in a G 1 L P N 13 U for S 3 C in a F 10 'R P' 1 U P is a B 1 F O the C N 9 U in A D
Hi Fibonacci - Lowest Perfect Number cannot be 1, as its divisors must not include itself, so is actually 6. Sorry, I don't have an alternative solution. ja
Hi again ,
Still thinking of 9 U in A D
Have asked one of my bridge partners who is a member of MENSA and she is thinking on it , also e-mailed it to one of my friends at Oxford University who is quite bright , who will ask around , but as yet no luck . Please let me know what the answer is if you get it before us . Thanks
Regards