ok i was doing a few quadratic equations examples for revision...and i came across some that im not totally sure how to do...can someone please explain??
one is:
solve this quadratic equation: x (x+4) = 0
the other one is:
rearrange into the form 'x^2 + bx + c = 0' then solve by factorising:
It's a long time since I did algebra, but this is how it goes I think!
everything you do to one side you must do to the other.
So start by multiplying out the left side & you get x2 (don't know how to right squared) +4x = 0
Re x(x + 4) = 0
If the product of two items is 0 then one or the other is 0.
So, if x(x + 4) = 0, either x = 0 or x+4 = 0.
Thus x = 0 or x + 4 = 0.
Hence x = 0 or x = -4.
Answers can be checked by substituting each value into the original equation.