ChatterBank0 min ago
Temperature and KC
How would the value for KC change with temperature?! In terms of endothermic and exothermic reactions?!
I understand that in a exothermic reaction, an increase in temperature isn't liked and as a result, the equilibrium is moved to the left, and in the case of an endothermic reactions, an increase in temperature favours the reaction and the equilibrium is moved to the right,
But what i dont quite understand is when there is a decrease in tempearture the equilibrium in an exothermic reaction, moves to the right...
Is that the same with an endothermic reaction or is the equilibrium moved to the left?!
I understand that in a exothermic reaction, an increase in temperature isn't liked and as a result, the equilibrium is moved to the left, and in the case of an endothermic reactions, an increase in temperature favours the reaction and the equilibrium is moved to the right,
But what i dont quite understand is when there is a decrease in tempearture the equilibrium in an exothermic reaction, moves to the right...
Is that the same with an endothermic reaction or is the equilibrium moved to the left?!
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