Body & Soul1 min ago
Help in Answering a geosystems question - please
" on her birthday, which happens to fall on september 21st, amelia is flying due east. as the sun rises and begins to bathe her elegant craft in golden light, the radio crackles and an announcer informs her- in a british accent, of course-that it is 2:00 pm greenwich time. hour after hour amelia maintains her course, cruising at an average speed of 105 miles per hour. all day long she sees nothing but water down below and when the sun sets she notes that only ten hours have elapsed since sunrise. along what line of latitude has amelia been traveling ? "
Answers
The date is on the equinox when the day is as long as the night (12 hours) all over the planet.
For her however the day only lasts 10 hours because she is flying towards the approaching terminator (line between day and night)
In that 10 hours she has travelled 1,050 miles (I'm assuming that's statute rather than nautical miles)
Assuming the Earth to...
In that 10 hours she has travelled 1,050 miles (I'm assuming that's statute rather than nautical miles)
10:29 Thu 07th Oct 2010
The date is on the equinox when the day is as long as the night (12 hours) all over the planet.
For her however the day only lasts 10 hours because she is flying towards the approaching terminator (line between day and night)
In that 10 hours she has travelled 1,050 miles (I'm assuming that's statute rather than nautical miles)
Assuming the Earth to be spherical the distance around the circle at lattitude x is 2*pi*radius*cos(x) (radius of the Earth 3960 miles)
so the 1050 miles represents the distance the terminator travels in 2 hours or 2/24 * that value
so 2/24 *2* pi * 3960 * cos(x) =1050
0.506=cos(x)
x = 59.57 degrees North or South
For her however the day only lasts 10 hours because she is flying towards the approaching terminator (line between day and night)
In that 10 hours she has travelled 1,050 miles (I'm assuming that's statute rather than nautical miles)
Assuming the Earth to be spherical the distance around the circle at lattitude x is 2*pi*radius*cos(x) (radius of the Earth 3960 miles)
so the 1050 miles represents the distance the terminator travels in 2 hours or 2/24 * that value
so 2/24 *2* pi * 3960 * cos(x) =1050
0.506=cos(x)
x = 59.57 degrees North or South
On second thoughts Nort - doesn't look as if there is any land at 60 degrees south
http://en.wikipedia.o...i/60th_parallel_south
http://en.wikipedia.o...i/60th_parallel_south
That would make it in BC http://confluence.org...e.php?lat=60&lon=-120
A very long way from the sea
GMT is an hour out then of course British Summer time is in play
A very long way from the sea
GMT is an hour out then of course British Summer time is in play
2pm gmt @ 15 degrees per hour = 120degrees west. BST is irrelevant in this case, I arrive at 60 degrees ( give or take a few minutes|)independantly. It should also be considerered that the altitude of the plane has not been given, this would make a significant difference to the times of sunrise and sunset so I am assuming that this additional complication which I believe is a tangential function has been ignored so I'm assuming that the plane is flying at sea level.
-- answer removed --
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