G C S E - Lines

[kuiperbelt]

The equation of a line L1 is

y = 6x – 1

and the equation of the line L2 is
​
4y – 24x - 8 = 0

Show that L1 and L2 are parallel.

[ClareTG0ld]

It's enough to divide the second equation by four and rearrange in the form y = mx + c, then compare gradients (x coefficient, ie m).

[bobbinwales]

Yes.... this is much more simpler than your usual ones..
The second equation is just y = 6x +22

So both have same steepness / gradient of 6

[kuiperbelt]

LOL If only he had drawn the graphs it would have been so obvious. Thank you both for pointing out the gradients being the same!!

BA to Clare because bobbin if you dont mind me saying, y = 6x +22 is not correct!!

[ToraToraTora]

divide equation 2 by 4 and you get the first.

[ToraToraTora]

you don't have to draw the graphs to work that out.

[perseverer]

Divide second by 4 and get y = 6x + 2 which may be what Bobb meant to type

[bobbinwales]

Yes ... my finger had a stutter.
y= 6x +2