ChatterBank3 mins ago
The Fly and the Train
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This is straight from the pub, so no apologies for this sounding daft.
Is this true...---->?
If a fly hits a train head on, it obviously loses. BUT - the force it's exerted on the train must surely have caused the train to slow down, even though we could probably never measure it as it's such a small relative force.
Is this true...---->?
If a fly hits a train head on, it obviously loses. BUT - the force it's exerted on the train must surely have caused the train to slow down, even though we could probably never measure it as it's such a small relative force.
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For more on marking an answer as the "Best Answer", please visit our FAQ.Sure... Newton said and proved that a body in motion tends to remain in motion (in a straight line) unless acted upon by an outside force... and secondly (pun only slightly intended) Newton gives us the fomula F = ma which, when applied to your scenario and given sufficient information could actually solve the ever so slight affect said fly has on said locomotive...You, of course, know the last thing to go through the fly's mind a nano-second prior to his demise, don;t you?
Oh, how I wish I was back in my old job (running a railway station). I used to love finding new ways of giving the reasons for delays. ('Leaves on the line', for example, would become "track adhesion difficulties due to vegetation debris on the railhead").
I'd really enjoy announcing "We apologise for the delay to this service. This was due to the locomotive suffering multiple collisions with calliphorae vomitoroa"
- or, in layman's terms, "It collided with a few bluebottles" ;-)
Chris
I'd really enjoy announcing "We apologise for the delay to this service. This was due to the locomotive suffering multiple collisions with calliphorae vomitoroa"
- or, in layman's terms, "It collided with a few bluebottles" ;-)
Chris
You can make an estimate of the effect. The total momentum of the train and the fly before and after the collision will be the same.
Let's say the train is 500 tonnes at 100 metres per second, and the fly is 1 gramme at 10 metres per second.
The total momentum is 49999999.99 kg ms(-1).
After the collision, the mass of train now includes the fly so its new v is 49999999.99/500000.001 ... or about 99.9999998 ms(-1).
So it is slowed by about one part in 50 million. It would be about a second late on a journey lasting a year and a half.
(i'm happy for someone to come up with a correction or two, it's easy to lose count of the decimal places!)
Let's say the train is 500 tonnes at 100 metres per second, and the fly is 1 gramme at 10 metres per second.
The total momentum is 49999999.99 kg ms(-1).
After the collision, the mass of train now includes the fly so its new v is 49999999.99/500000.001 ... or about 99.9999998 ms(-1).
So it is slowed by about one part in 50 million. It would be about a second late on a journey lasting a year and a half.
(i'm happy for someone to come up with a correction or two, it's easy to lose count of the decimal places!)
The original argument (as I recall it from my youth) is that, since the fly must come to a stop before it reverses direction, then the train, too, must come to a stop.
Obviously the train doesn't stop, but nor does it slow down.
Only a molecule of two of the steel on the front of the engine would be affected, causing a miniscule denting, probably too small ever to be measured. If anything stops, it's only these couple of molecules. The compression of the steel would create a tiny amount of heat that would dissipate immediately, and, given the elasticity of the steel, the dent would bounce back to to form near enough the shape of the original smooth surface.
That's how I worked it out, all those years ago.
Obviously the train doesn't stop, but nor does it slow down.
Only a molecule of two of the steel on the front of the engine would be affected, causing a miniscule denting, probably too small ever to be measured. If anything stops, it's only these couple of molecules. The compression of the steel would create a tiny amount of heat that would dissipate immediately, and, given the elasticity of the steel, the dent would bounce back to to form near enough the shape of the original smooth surface.
That's how I worked it out, all those years ago.
if you do not have a fly swatter to hand when you actually need one, it is much more effective to attempt to swat the fly simultaneously from two opposite directions.
This appears to outwit the fly's reactions.
Using two large, heavy books gives a very satisfying thud, as well, as the fly gets laterally compressed to a lethal degree - or splatted, in common parlance.
This appears to outwit the fly's reactions.
Using two large, heavy books gives a very satisfying thud, as well, as the fly gets laterally compressed to a lethal degree - or splatted, in common parlance.
I hate to be pedantic, but I don't like to see people making flase (or inaccurate) statements....
It does matter what it's made of, the fly is like a crumple zone on a car... It would compress, increasing the deceleration time, reducing the overall force. As we know, the change in momentum (MV-MU) is equal to Force x Time (Ft); Ft=MV-MU, F=(MV-MU)/t, to as t (the time taken for the complete deceleration of the fly through it's inevitable splattering), increases, the force exerted on the train decreases proportionally. So, if the fly has just eaten his dinner, he'll be stopping the train for a bit longer than if he is on his way out for dinner.
It does matter what it's made of, the fly is like a crumple zone on a car... It would compress, increasing the deceleration time, reducing the overall force. As we know, the change in momentum (MV-MU) is equal to Force x Time (Ft); Ft=MV-MU, F=(MV-MU)/t, to as t (the time taken for the complete deceleration of the fly through it's inevitable splattering), increases, the force exerted on the train decreases proportionally. So, if the fly has just eaten his dinner, he'll be stopping the train for a bit longer than if he is on his way out for dinner.