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frannie38 | 14:25 Sat 06th Jun 2009 | Sport
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What is the minimum amount of points that can win a frame of snooker (assuming the opponent does not con cede) would be grateful for any help please
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I think it's 22!

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thank you dasherman.
I believe the answer is 24, for what it's now worth- although please correct me if I calculated this wrong:

Person A pots all the reds on the table, but fails to pot any colours subsequently:
Person A now has 15 points (15 x 1 for each red). There are currently 27 points now left available on the table (2+3+4+5+6+7 for each of the colours, yellow through to black.)
If person A then pots the yellow, (s)he has 17 points; 25 left on the table.
If person A pots the green, (s)he will have 20 points; 22 left on the table.
If person A now pots the brown, (s)he will have 24 points; leaving 18 on the table.
Thus, 24 points is the minimum I calculate person A to need, presuming that person B doesn't start looking for snookers.
The way I worked it out is:-

Player A pots 13 reds with no subsequent colours therefore scores 13 points.

Player B then pots 2 reds with no subsequent colours and then pots yellow(2),green(3),brown(4),blue(5),pink(6) giving him 22 points.

With just the black ball remaining and a snooker needed the game is effectively over.

Having done a bit of online research I think the theoretical albeit highly unlikely answer (although endorsed by Steve Davis) is actually 16.

Player A pots all 15 reds and the cue ball in one shot,score is therefore Player A 0 - 4 Player B.

The colours are then potted in this sequence:-

Yellow(2) - Player B
Green(3) - Player B
Brown(4) - Player A
Blue (5) - Player A
Pink(6) - Player A
Black(7) - Player B

Final Score:-
Player A 15 - 16 Player B

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