ChatterBank1 min ago
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In a sports contest there were m medals awarded on n successive days (n > 1). On the first day 1 medal and 1/7 of the remaining m - 1 medals were awarded.
On the second day 2 medals and 1/7 of the now remaining medals was awarded; and so on.
On the nth and last day, the remaining n medals were awarded. How many days did the contest last, and how many medals were awarded altogether?
On the second day 2 medals and 1/7 of the now remaining medals was awarded; and so on.
On the nth and last day, the remaining n medals were awarded. How many days did the contest last, and how many medals were awarded altogether?
Answers
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Using the notatation M, L and k to denote Medals awarded, those Left and Day number, then
M(k) = k + 1/7* [L(k-1) -k]
and
L(k) = L(k-1) - M(k). This system of equations needs careful thought.
Using the notatation M, L and k to denote Medals awarded, those Left and Day number, then
M(k) = k + 1/7* [L(k-1) -k]
and
L(k) = L(k-1) - M(k). This system of equations needs careful thought.