ChatterBank9 mins ago
Please Help Me With This Physics Exercise
How fast will a 4-meter long car need to go in order to fit inside of a 3-meter long garage? (answers in terms of c, the speed of light)
Thanks in advance!
Thanks in advance!
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https:/ /scienc e.howst uffwork s.com/s cience- vs-myth /everyd ay-myth s/relat ivity9. htm
Good luck I would'nt know where to start
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Good luck I would'nt know where to start
Incredz Lorentz around 30 y before Einstein did his stuff
said, "if you reduce by 1 - v2/c2 - square root of.... ( look p Lorentz contraction) - call this r, then it all comes out in the wash"
can anyone see the speed is gonna have to be half-c ?
L = Lo times r - - - - -r here is 1 minus v2/c2 ( sq rt)
3 = 4 r leads to 9/16 = r2
kick around - - 7 /16 = v2/c2
so v is root7 / 4 times c
I can do it better on a piece of paper - google Lorentz contraction
said, "if you reduce by 1 - v2/c2 - square root of.... ( look p Lorentz contraction) - call this r, then it all comes out in the wash"
can anyone see the speed is gonna have to be half-c ?
L = Lo times r - - - - -r here is 1 minus v2/c2 ( sq rt)
3 = 4 r leads to 9/16 = r2
kick around - - 7 /16 = v2/c2
so v is root7 / 4 times c
I can do it better on a piece of paper - google Lorentz contraction
Now seriously folks
this is a classical problem
Car is 1 cm longer than the garage
the car goes at such a speed that it is now the length of the garage by reason of Lorentz contraction - that pretty near 'c' !
as the car exhaust passes an observer at the door, he closes it.
What happens then ?
( does the back of the car explode thro the garage doors a fraction of a second later?)
and and and the answer is....
time is local so the observer's time is t1 and the drivers time is t2
and they are not able to agree when the car has completely passed into the garage
Physics course 1970
this is a classical problem
Car is 1 cm longer than the garage
the car goes at such a speed that it is now the length of the garage by reason of Lorentz contraction - that pretty near 'c' !
as the car exhaust passes an observer at the door, he closes it.
What happens then ?
( does the back of the car explode thro the garage doors a fraction of a second later?)
and and and the answer is....
time is local so the observer's time is t1 and the drivers time is t2
and they are not able to agree when the car has completely passed into the garage
Physics course 1970