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An Easy Way To Work It Out?
16 Answers
One of the questions on 1% which was on TV on Saturday was along the lines of,
If a bat and ball cost £1.10 and the bat cost £1 more than the ball, how much was the ball?
I just couldn't work this out and wondered if there is an easy understandable way to do it. TIA
If a bat and ball cost £1.10 and the bat cost £1 more than the ball, how much was the ball?
I just couldn't work this out and wondered if there is an easy understandable way to do it. TIA
Answers
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For more on marking an answer as the "Best Answer", please visit our FAQ.Take the difference between the two items (£1) from the overall total (£1.10) then divide that answer (10p) by two to get the cost of the lower priced item (5p).
That works for any other prices
Pen and paper cost £10 and the pen cost £7 more than the paper, how much was the paper?
£10-£7 = £3
£3 ÷ 2 = £1.50
The paper cost £1.50 and the pen cost £8.50.
That works for any other prices
Pen and paper cost £10 and the pen cost £7 more than the paper, how much was the paper?
£10-£7 = £3
£3 ÷ 2 = £1.50
The paper cost £1.50 and the pen cost £8.50.
Gingebee's algebraic answer is correct although it would help if you can remember how to solve simultaneous equations.
In words I would try to explain that as the bat cost £1 more than the ball if you take a £1 off the total you can assume they cost the same at a total of 10p so 5p each. Put the £1 back on the bat and you get 5p and £1.05.
In words I would try to explain that as the bat cost £1 more than the ball if you take a £1 off the total you can assume they cost the same at a total of 10p so 5p each. Put the £1 back on the bat and you get 5p and £1.05.
This is one of those cases where a 'common sense' or a 'trial and error' is actually far simpler than a mathematical one. The ball clearly can't cost very much, so there are only a few options to try and it should be easy enough to get there quickly.
Doing it mathematically means delving into simultaneous equations, as follows:
Let the price of the bat be x and the price of the ball be y.
Then, working in pence, x + y = 110 [Equation 1] because we're told that the total price is 110p.
Also, x - y = 100 [Equation 2] because we know that the difference in the prices is 100p.
Adding Equation 1 to Equation 2 yields
2x = 210
Dividing both sides by 2 gives us
x = 105
Substituting back into Equation 1 then gives
105 + y = 110
Subtracting 105 from both sides leaves us with
y = 5
Doing it mathematically means delving into simultaneous equations, as follows:
Let the price of the bat be x and the price of the ball be y.
Then, working in pence, x + y = 110 [Equation 1] because we're told that the total price is 110p.
Also, x - y = 100 [Equation 2] because we know that the difference in the prices is 100p.
Adding Equation 1 to Equation 2 yields
2x = 210
Dividing both sides by 2 gives us
x = 105
Substituting back into Equation 1 then gives
105 + y = 110
Subtracting 105 from both sides leaves us with
y = 5
Since I posted this question, I see it was asked on Barry's thread by Sharon and was answered by Ferlew in a way I understand.
Sorry I can't give BA as it has also been answered the same way on here by Corby and Prudie, but thanks to you both anyway.
I went to the kind of school (way back in the day) when we were actually asked in the maths class if we would like to learn Algebra and the majority said no!
We obviously didn't think it might come in handy one day.
Thanks to all.
Sorry I can't give BA as it has also been answered the same way on here by Corby and Prudie, but thanks to you both anyway.
I went to the kind of school (way back in the day) when we were actually asked in the maths class if we would like to learn Algebra and the majority said no!
We obviously didn't think it might come in handy one day.
Thanks to all.
oh yeah jokey
you know the problem: two trains 30 miles apart start go towards each other. One at ten mpoh and the other at 20 mph Fly flies to and fro between them at 75 mi an hour - how far does it fly? ( er before the trains crash )
and they asked a prof of engineering who hesitated and said 75 m
and the student said o god well done - most people try to sum the decreasing series as the fly goes in between the approaching trains
and the prof said - - I did
( trains crash after an hour and the fly therefore flies for an hour at 75 mph)
you know the problem: two trains 30 miles apart start go towards each other. One at ten mpoh and the other at 20 mph Fly flies to and fro between them at 75 mi an hour - how far does it fly? ( er before the trains crash )
and they asked a prof of engineering who hesitated and said 75 m
and the student said o god well done - most people try to sum the decreasing series as the fly goes in between the approaching trains
and the prof said - - I did
( trains crash after an hour and the fly therefore flies for an hour at 75 mph)