ChatterBank3 mins ago
Beer's Law
A solution containing 3.5 mmoles/l of an absorbing compound was diluted 1 in 80 and then read at 670nm in a spectrophotometer using a 1cm sample holder.
If the measured aborbance was 0.37, what was the corresponding transmittance?Calculate the molor absoptivity of the compound at the wavelength used.
If the measured aborbance was 0.37, what was the corresponding transmittance?Calculate the molor absoptivity of the compound at the wavelength used.
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For more on marking an answer as the "Best Answer", please visit our FAQ.thanks guys for the help!! and your concerns bout not wanting me to fail 'eltelioni'!! but 'factor 30' its not that i just want the answer for homework i really want to understand how u guys were able to work it out so i know for future reference. i just cant seem to figure it out how you guys mastered the answer 42???
This could be tricky in plain text, but here goes.
A = absorbance
T = transmittance
I = intensity of light after passing through the sample
J = intensity of the light before passing through the sample
A = -log(I/J) using log to base 10
and T = I/J
so A= -log(T)
so T = 10^(-A) (10 raised to the power -A)
so T = 10^(-0.37)
using Google as a calculator, that gives 0.426579519
which I would round to 0.43
Transmittance is often expressed as a percentage, so multiply by a hundred to give 43.
A = absorbance
T = transmittance
I = intensity of light after passing through the sample
J = intensity of the light before passing through the sample
A = -log(I/J) using log to base 10
and T = I/J
so A= -log(T)
so T = 10^(-A) (10 raised to the power -A)
so T = 10^(-0.37)
using Google as a calculator, that gives 0.426579519
which I would round to 0.43
Transmittance is often expressed as a percentage, so multiply by a hundred to give 43.