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Golf: 8 players, 3 days and two fourballs per day.

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bluenose71 | 11:53 Thu 25th Jun 2009 | Quizzes & Puzzles
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Need to combine 8 players into 3 days (2x four balls per day), so everybody plays with everybody at least once, and no more than twice!

Can it be done?

Thank you
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Don't think it's pssible. Take player A, who has 7 potential partners for 6 matches, with three being used for each match. After five matches, he will have used 15 partners. After 5 matches, he will have played with at least five of his partners twice.
Dunno but, if players are: A,B,C,D,E,F,G,H.--Day 1 ABCD/ EFGH & ABEF/CDGH. Day 2 ACEG/BDFH & ADGH/BCEF Day 3 BDGH/ACEF & ACEH/BDFG, is it possible?

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Golf: 8 players, 3 days and two fourballs per day.

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